-n^2-n+21=0

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Solution for -n^2-n+21=0 equation:



-n^2-n+21=0
We add all the numbers together, and all the variables
-1n^2-1n+21=0
a = -1; b = -1; c = +21;
Δ = b2-4ac
Δ = -12-4·(-1)·21
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{85}}{2*-1}=\frac{1-\sqrt{85}}{-2} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{85}}{2*-1}=\frac{1+\sqrt{85}}{-2} $

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